p06.cpp
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/*
Sum square difference
Problem 6
The sum of the squares of the first ten natural numbers is,
12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
*/
#include <stdio.h>
#include <math.h>
using namespace std;
#define LIMITE_RANGO 100
int main(int argc, char const *argv[])
{
int i = 0;
int res = 0;
int valSum = 0;
int valPow = 0;
while(i++ < LIMITE_RANGO)
{
valSum += i;
valPow += pow(i, 2);
}
res = pow(valSum, 2) - valPow;
printf("Resultado final: %d\n", res);
return 0;
}