/*

Multiples of 3 and 5
Problem 1
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.

By: dbk

*/

#include <iostream>
#include <stdio.h>

using namespace std;

int main()
{
	int res = 0;

	for (int i = 1; i < 1000; i++)
	{
		res += (i % 3 == 0 || i % 5 == 0) ? i : 0;
	}

	printf("Resultado: %i\n", res);

	return 0;
}