/*
  
  Sum square difference
  Problem 6
  The sum of the squares of the first ten natural numbers is,
  
  12 + 22 + ... + 102 = 385
  The square of the sum of the first ten natural numbers is,
  
  (1 + 2 + ... + 10)2 = 552 = 3025
  Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
  
  Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
  
  */
  
  #include <stdio.h>
  #include <math.h>
  
  using namespace std;
  
  #define LIMITE_RANGO 100
  
  int main(int argc, char const *argv[])
  {
  
  	int i = 0;
  	int res = 0;
  	int valSum = 0;
  	int valPow = 0;
  
  	while(i++ < LIMITE_RANGO)
  	{
  		valSum += i;
  		valPow += pow(i, 2);
  	}
  
  	res = pow(valSum, 2) - valPow;
  	printf("Resultado final: %d
  ", res);
  
  	return 0;
  }