/*
  
  Multiples of 3 and 5
  Problem 1
  If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
  Find the sum of all the multiples of 3 or 5 below 1000.
  
  By: dbk
  
  */
  
  #include <iostream>
  #include <stdio.h>
  
  using namespace std;
  
  int main()
  {
  	int res = 0;
  
  	for (int i = 1; i < 1000; i++)
  	{
  		res += (i % 3 == 0 || i % 5 == 0) ? i : 0;
  	}
  
  	printf("Resultado: %i
  ", res);
  
  	return 0;
  }